It cant be factorised using all the methods given due 2 the fact that the equation is in its simplest form i.e it can be factorised, unless the equation is being altered somehow
x^2+x+1 doesn't have any real roots (decriminant is the square root of negative 3, which doesn't exist on the real plane) hence why you can factorise it using a normal method. Try checking out the curve of the equation to see what i mean!
13 comments:
it cant be factorised,the x in the question should be 2x................hmmm...not too sure but thats my ans! =D
it cnt be factorised cuz the x in the question should be 2x...i think...mayb?
It cant be factorised using all the methods given due 2 the fact that the equation is in its simplest form i.e it can be factorised, unless the equation is being altered somehow
I do not think it can be factorised with either 2 method as the middle term should b 2x not 2 sure but thats my ans
canbe factorise but canot find the answer
obvious cant factorise b'cause x2+x+1 is nt possible cos the x nid 2 be a 2x for it to be able to factorise.........yup!I'm sure XD
tsk tsk tsk...hmmmmm
cannot factorise!...
thts my final answer...
ps. eugene copy andhika
Yes, most of u are correct! he expression (not equation, Grace) can't be factorised at all.
And good suggestion raised, if the expression is x²+2x+1, then it can be factorised as (x+1)².
Can u give an example of a quadratic expression that can be factorised if it starts with 2x²?
it can't be factorised
the 'x' in the question must have a coefficient as 2,then can it be factorised ...i think so
it can't be factorised.
x in e question shld b 2x, then it can be factorised. [ehh, not sure not sure eh..]
for the 2x²,
how about trying 2x²+3x+27.
i think it should be able to factorise.
x^2+x+1 doesn't have any real roots (decriminant is the square root of negative 3, which doesn't exist on the real plane) hence why you can factorise it using a normal method. Try checking out the curve of the equation to see what i mean!
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